2c^2-5c-18=0

Solution for 2c^2-5c-18=0 equation:

Simplifying
2c2 + -5c + -18 = 0

Reorder the terms:
-18 + -5c + 2c2 = 0

Solving
-18 + -5c + 2c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-2 + -1c)(9 + -2c) = 0

Subproblem 1
Set the factor '(-2 + -1c)' equal to zero and attempt to solve:

Simplifying
-2 + -1c = 0

Solving
-2 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -1c = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -1c = 0 + 2
-1c = 0 + 2

Combine like terms: 0 + 2 = 2
-1c = 2

Divide each side by '-1'.
c = -2

Simplifying
c = -2
Subproblem 2
Set the factor '(9 + -2c)' equal to zero and attempt to solve:

Simplifying
9 + -2c = 0

Solving
9 + -2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -2c = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -2c = 0 + -9
-2c = 0 + -9

Combine like terms: 0 + -9 = -9
-2c = -9

Divide each side by '-2'.
c = 4.5

Simplifying
c = 4.5
Solution
c = {-2, 4.5}